If ccos3θ+3ccosθsin2θ=m, csin3θ+3ccos3θsinθ=n, then prove that (m+n)2/3+(m−n)2/3=2c2/3.
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Solution
Adding the given relation, we get c(sinθ+cosθ)3=m+n or c2/3(sinθ+cosθ)3=(m+n)2/3. Similarly, by subtracting, we shall get c2/3(sinθ+cosθ)2=(m+n)2/3 Now add (1) and (2).