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Question

If ccos3θ+3ccosθsin2θ=m,
csin3θ+3ccos3θsinθ=n, then prove that
(m+n)2/3+(mn)2/3=2c2/3.

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Solution

Adding the given relation, we get
c(sinθ+cosθ)3=m+n
or c2/3(sinθ+cosθ)3=(m+n)2/3.
Similarly, by subtracting, we shall get
c2/3(sinθ+cosθ)2=(m+n)2/3
Now add (1) and (2).
(m+n)2/3+(mn)2/3=2c2/3.

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