If Cdiamond- Cgraphite- H-ve - This means -

From the given equation, Δ H =Δ H_G Δ H_D= ve Here the reaction is exothermic, heat releases from the reaction because Δ H value is negative. ∴ Graphite is more ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Introduction

If Cdiamond→ ...

Question

If $C_{d i a m o n d} \to C_{g r a p h i t e}; Δ H = - v e$ . This means :

Graphite is more stable form than diamond

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Graphite has more energy than diamond

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Both are equally stable form

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Stability of form can not be predicted by

Δ H

values

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A Graphite is more stable form than diamond
From the given equation,
$Δ H = Δ H_{G} - Δ H_{D} = - v e$
Here the reaction is exthermic heta releases from the reaction because $Δ H$ value is negative.
$∴$ Grahite more stable than diamond.

Suggest Corrections

Similar questions

Q. If

C_{d i a m o n d} ⟶ C_{g r a p h i t e}; Δ H = - v e

. This means :

Q. If

C_{d i a m o n d} \to C_{g r a p h i t e}; Δ H = - v e .

This implies:

Calculate $Δ H$ for $C_{(g r a p h i t e)} \to C_{d i a m o n d}$ from the following data:

i) $C (g r a p h i t e) + O_{2} \to C O_{2} (g), Δ H = - 94 K c a l$

ii) $C (d i a m o n d) + O_{2} \to C O_{2} (g), Δ H = - 68 K c a l$

Q. Determine the heat of transformation of

C_{(d i a m o n d)} \to C_{(g r a p h i t e)}

from the following data

C_{(d i a m o n d)} + O_{2} (g) \to C {C O}_{2} (g); (Δ H = - 94.5 k c a l)

C_{(g r a p h i t e)} + O_{2} (g) \to C {C O}_{2} (g); (Δ H = - 94.0 k c a l)

Q. For the following reaction :

C_{D i a m o n d} + O_{2} \to C O_{2} (g); Δ H = - 94.3 k c a l

C_{G r a p h i t e} + O_{2} \to C O_{2} (g); Δ H = - 97.6 k c a l

The heat required to change 1 g of

C_{d i a m o n d} \to C_{g r a p h i t e}

is:

Join BYJU'S Learning Program

If Cdiamond→Cgraphite;ΔH=−ve . This means :

The correct option is A Graphite is more stable form than diamond From the given equation, ΔH=ΔHG−ΔHD=−ve Here the reaction is exthermic heta releases from the reaction because ΔH value is negative. ∴ Grahite more stable than diamond.

If $C_{d i a m o n d} \to C_{g r a p h i t e}; Δ H = - v e$ . This means :

The correct option is A Graphite is more stable form than diamond
From the given equation,
$Δ H = Δ H_{G} - Δ H_{D} = - v e$
Here the reaction is exthermic heta releases from the reaction because $Δ H$ value is negative.
$∴$ Grahite more stable than diamond.