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Question

If CnCn2+Cn1Cn3+Cn2Cn4+...+C3C1+C2C0=2nCnλ where Ci=nCi,λN, then find the value of λ

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Solution

C0C2+C1C3+C2C4+..........+Cn2Cn=2nCn+2
(1+x)n=nC0+nC1x+nC2x2+nC3x3+......+nCnxn........(1)
(x+1)n=nC0xn+nC1xn1+nC2xn2+......+nCn........(2)
multiplying equation (1) & (2)
(1+x)2n=(nC0+nC1x+nC2x2+....+nCnxn)(nC0xn+nC1xn1+nC2xn2+......+nCn).
Now required expression is coefficient of xn2in(1+x)2n=2nCn2=2nCn+2

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