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Question

If Cn is the coefficient of xn in the expansion of (1+x)n then C1+2.C2+3.C3++n.Cn=

A
2n
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B
n.2n
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C
n.2n+1
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D
n.2n1
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Solution

The correct option is D n.2n1
(1+xn)=nr=0Crxn= nC0x0+nC1x+nC2x2+.....+nCnxn
Now,(1+xn)=C0+C1x+C2x2+.....+Cnxn ..(1)
Differentiating (1) w.r.t x
n(1+x)n1=C1+2C2x+.....+nCnxn1 ..(2)
put x=1 and get,
n2n1=C1+2C2+.....+nCn
C1+2C2+.....+nCn=n.2n1

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