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Specific Heat Capacity

If C p and C...

Question

If C $_{p}$ and C $_{v}$ denote the specific heats of nitrogen per unit mass at constant pressure and constant volume respectively, then

A

C_{p} - C_{v} = \frac{R}{28}

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B

C_{p} - C_{v} = \frac{R}{14}

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C

C_{p} - C_{v} = R

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D

C_{p} - C_{v} = 28 R

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Solution

The correct option is D $C_{p} - C_{v} = \frac{R}{28}$
For any gas: $C_{P} - C_{V} = R_{u} R_{u} = \frac{R}{m o l a r m a s s}$
Molar mass of nitrogen = $2 \times 14 = 28$
$∴ F o r N_{2}, R_{u} = \frac{R}{28} = C_{P} - C_{V}$

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