If cp and cv denotes the specific heat of nitrogen at constant pressure and constant volume respectively, then
A
cp−cv=28R
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B
cp−cv=R28
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C
cp−cv=R14
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D
cp−cv=R
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Solution
The correct option is Bcp−cv=R28 Molar heat capacity=Molar mass× specific heat capacity ⇒CP=Mcp&CV=Mcv...(i) CP−CV=R...(ii)
From Eq (i)&(ii), Mcp−Mcv=R 28cp−28cv=R ∴cp−cv=R28