Question

If CAT 2009 contains 150 questions and each question contains 5 options, find the total number of ways in which a student can answer atleast two out of 150 questions.

A
5150 -601
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B
6150-751
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C
4150-601
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D
6150-601
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E
none of these
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Solution

The correct option is B 6150-751Option (b) As a student may answer a question or he may not, So let’s verify the total chances that he can take with a question, i.e. He can take 6 chances with a question namely A,B,C,D,E or not answering it. So with every question he can take 6 chances. So total number of chances is 6150 From this, we have to deduct these chances: - Total number of ways of answering zero questions as well as one question exactly, which is 1 + (150 × 5) = 751. So answer is 6150 – 751.

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