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Question

If certain number of bulbs rated as (P1 watt, V volt), (P2 watt, V volt)... are connected in series across a potential difference of V volt, then power 'P' consumed by all bulbs is given as

A
P=P1+P2+P3 ........
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B
1P=1P1+1P2+1P3 ........
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C
P2=P21+P22+P23 ........
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D
None of these
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Solution

The correct option is D 1P=1P1+1P2+1P3 ........
Power consumed in one bulb rated as P1W,Vvolt having resistance of R1Ω is
P1=V2R1 .........(1)
For certain number of bulbs we can write,
P2=V2R2 .........(2)
P3=V2R3 and so on..........(3)
We know in series combination resistances get added, hence

Req=R1+R2+R3+...........

dividing both sides by V2, we get

ReqV2=R1V2+R2V2+R3V2+........

Referring equations (1),(2) and (3)

1Peq=1P1+1P2+1P3+........

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