If 1 - 2x-1 1- 2x-1 n - 1- 2x-1 n - a 0 - a 1 x- a 2 x 2 - a n x n then n must be equal to

The correct option is A 21,22 1 √( 2x+1 ) nbsp; {( 1+√( 2x+1 ) nbsp; ) nbsp; ^ n ( 1 √( 2x+1 ) nbsp; ) nbsp; ^ n } =2{ _ nbsp; ^ n ...

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Polynomial Functions

If 1 √ 2x+1...

Question

If $\frac{1}{\sqrt{2 x + 1}} {{(1 + \sqrt{2 x + 1})}^{n} - {(1 - \sqrt{2 x + 1})}^{n}} = a_{0} + a_{1} x + a_{2} x^{2} + . . . . + a_{n} x^{n}$ then $n$ must be equal to

20, 21

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21, 22

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22, 23

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none of these

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Similar questions

(1 - x)^{- n} = a_{0} + a_{1} x + a_{2} x^{2} + . . . . . . . . + a_{r} x^{r} + . . . . .

a_{0} + a_{1} + a_{2} + . . . . . . + a_{r}

{(1 + 2 x + 3 x^{2})}^{10} = a_{0} + a_{1} x + a_{2} x^{2} + . . . . . + a_{20} x^{20}

a_{1}

n

{(1 + x)}^{n} = a_{0} + a_{1} x + a_{2} x^{2} + \dots + a_{n} x^{n}

a_{0} + a_{1} + a_{2} + \dots + a_{n}

{(1 + 2 x + 3 x^{2})}^{10} = a_{0} + a_{1} x + a_{2} x^{2} + . . . . + a_{20} x^{20}

x^{n - 1}

E = {(2 x + 1)}^{n - 1} + {(2 x + 1)}^{n - 2} (x + 1) + . . . . + {(x + 1)}^{n - 1}

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