If 2017 x-2017 - 2018 y-2018 - 2019 x-2019 -2015- then x x-2017 - y y-2018 - z z-2019 equals

The correct option is B 2018 We know that, ba+b=1 aa+b #160;using this xx+2017+yy+2018+zz+2019 =3 2017x+2017 2018y+2018 2019z+2019 = ...

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Byju's Answer

Standard XII

Mathematics

Intersection of Sets

If 2017 x+2...

Question

If $\frac{2017}{x + 2017} + \frac{2018}{y + 2018} + \frac{2019}{x + 2019} = - 2015$ , then $\frac{x}{x + 2017} + \frac{y}{y + 2018} + \frac{z}{z + 2019}$ equals

2017

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2018

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2019

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2016

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Solution

The correct option is B $2018$
We know that,
$\frac{b}{a + b} = 1 - \frac{a}{a + b}$

using this $\frac{x}{x + 2017} + \frac{y}{y + 2018} + \frac{z}{z + 2019}$

$= 3 - \frac{2017}{x + 2017} - \frac{2018}{y + 2018} - \frac{2019}{z + 2019}$

$= 3 - (- 2015)$

$= 2018$

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Similar questions

Q. If

\frac{2017}{x + 2017} + \frac{2018}{y + 2018} + \frac{2019}{z + 2019} = - 2015

, then

\frac{x}{x + 2017} + \frac{y}{y + 2018} + \frac{z}{z + 2019}

equals ?

The remainder when the determinant

∣ ∣ ∣ ∣ ∣ \begin{matrix} 2014^{2014} & 2015^{2015} & 2016^{2016} 2017^{2017} & 2018^{2018} & 2019^{2019} 2020^{2020} & 2021^{2021} & 2022^{2022} \end{matrix} ∣ ∣ ∣ ∣ ∣

is divided by

5

is.

The remainder when the determinant

$∣ ∣ ∣ ∣ ∣ \begin{matrix} 2014^{2014} & 2015^{2015} & 2016^{2016} 2017^{2017} & 2018^{2018} & 2019^{2019} 2020^{2020} & 2021^{2021} & 2022^{2022} \end{matrix} ∣ ∣ ∣ ∣ ∣$

is divided by 5 is.

Q. The remainder when the determinant

∣ ∣ ∣ ∣ ∣ \begin{matrix} 2014^{2014} & 2015^{2015} & 2016^{2016} 2017^{2017} & 2018^{2018} & 2019^{2019} 2020^{2020} & 2021^{2021} & 2022^{2022} \end{matrix} ∣ ∣ ∣ ∣ ∣

is divided by

5

Q. The population of rabbits over a duration in a zoo is tabulated as follows:
Year Population of Rabbit
(in thousand)

2015	3
2016	5
2017	6
2018	7
2019	8
2020	9

Choose the line graph that correctly depicts the data set.

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If 2017x+2017+2018y+2018+2019x+2019=−2015, then xx+2017+yy+2018+zz+2019 equals

The correct option is B 2018We know that,ba+b=1−aa+b using this xx+2017+yy+2018+zz+2019=3−2017x+2017−2018y+2018−2019z+2019=3−(−2015)=2018

If $\frac{2017}{x + 2017} + \frac{2018}{y + 2018} + \frac{2019}{x + 2019} = - 2015$ , then $\frac{x}{x + 2017} + \frac{y}{y + 2018} + \frac{z}{z + 2019}$ equals

The correct option is B $2018$
We know that,
$\frac{b}{a + b} = 1 - \frac{a}{a + b}$

using this $\frac{x}{x + 2017} + \frac{y}{y + 2018} + \frac{z}{z + 2019}$

$= 3 - \frac{2017}{x + 2017} - \frac{2018}{y + 2018} - \frac{2019}{z + 2019}$

$= 3 - (- 2015)$

$= 2018$