If 2x-33x-2-23- then the value of x is-

The correct option is B 512 If 2x 33x+2= 23 or 3(2x 3)= 2(3x+2) or 6x 9= 6x 4 or 12x=5 ∴ x=512 ...

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If 2x-33x+2...

Question

If $\frac{2 x - 3}{3 x + 2} = - \frac{2}{3}$ , then the value of $x$ is-

\frac{5}{12}

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- \frac{3}{11}

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\frac{7}{12}

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\frac{6}{13}

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Solution

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x = \frac{1}{(2 - \sqrt{3})}

\frac{1}{(1 + \sqrt{2})} + \frac{1}{(\sqrt{2} + \sqrt{3})} + \frac{1}{(\sqrt{3} + \sqrt{4})} + . . . . . . + \frac{1}{(\sqrt{8} + \sqrt{9})}

\frac{2 x}{3} - \frac{3 x}{8} = \frac{7}{12}

x

Re-arrange suitably and find the sum in each of the following :

(i) $\frac{11}{12} + \frac{- 17}{3} + \frac{11}{2} + \frac{- 25}{2}$

(ii) $\frac{- 6}{7} + \frac{- 5}{6} + \frac{- 4}{9} + \frac{- 15}{7}$

(iii) $\frac{3}{5} + \frac{7}{3} + \frac{9}{5} + \frac{- 13}{15} + \frac{- 7}{3}$

(iv) $\frac{4}{13} + \frac{- 5}{8} + \frac{- 8}{13} + \frac{9}{13}$

(v) $\frac{2}{3} + \frac{- 4}{5} + \frac{1}{3} + \frac{2}{5}$

(vi) $\frac{1}{8} + \frac{5}{12} + \frac{2}{7} + \frac{7}{12} + \frac{9}{7} + \frac{- 5}{16}$

| x + 2 | + | 2 x + 6 | + | 3 x - 3 | = 12

∣ ∣ ∣ ∣ ∣ \begin{matrix} x^{2} + x & x + 1 & x - 2 {2 x}^{2} + 3 x - 1 & 3 x & 3 x - 3 x^{2} + 2 x + 3 & 2 x - 1 & 2 x - 1 \end{matrix} ∣ ∣ ∣ ∣ ∣ = a x - 12,

a^{2}

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