Question

If $\frac{a}{b}=\frac{7}{3}$, then find the value of $\frac{5a+3b}{5a-3b}$.

• A. $\frac{21}{13}$
• B. $\frac{22}{13}$
• C. $\frac{19}{15}$
• D. $\frac{22}{15}$

Answer 1

Answer: (B)

$\frac{22}{13}$

We have,

$\frac{a}{b}=\frac{7}{3}$

Since,

$\frac{5a+3b}{5a-3b}$

$\Rightarrow \frac{\frac{5a}{b}+3}{\frac{5a}{b}-3}$

Put the value of $\frac{a}{b}$

Therefore,

$\Rightarrow \frac{5\times \frac{7}{3}+3}{5\times \frac{7}{3}-3}$

$\Rightarrow \frac{\frac{35}{3}+3}{\frac{35}{3}-3}$

$\Rightarrow \frac{\frac{35+9}{3}}{\frac{35-9}{3}}$

$\Rightarrow \frac{44}{26}$

$\Rightarrow \frac{22}{13}$

Hence, this is the answer.