If x2-15 - x3-14- then x - m10- So- m is-

The correct option is C 27 x 2 1 5 = x 3 + 1 4 30x 12 60 #160;= 20x +15 60 10x = 27 x = 27 10 #160;= 2 7 10 ...

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Standard VII

Mathematics

Percentages

If x2-15 = ...

Question

If $\frac{x}{2} - \frac{1}{5} = \frac{x}{3} + \frac{1}{4}$ , then $x = \frac{m}{10}$ . So, $m$ is:

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Solution

The correct option is C $27$
$\frac{x}{2} - \frac{1}{5} = \frac{x}{3} + \frac{1}{4}$
$\frac{30 x - 12}{60} = \frac{20 x + 15}{60}$
$10 x = 27$
$x = \frac{27}{10} = 2 \frac{7}{10}$

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If x2−15=x3+14, then x=m10. So, m is:

The correct option is C 27x2−15=x3+1430x−1260=20x+156010x=27x=2710=2710

If $\frac{x}{2} - \frac{1}{5} = \frac{x}{3} + \frac{1}{4}$ , then $x = \frac{m}{10}$ . So, $m$ is:

The correct option is C $27$
$\frac{x}{2} - \frac{1}{5} = \frac{x}{3} + \frac{1}{4}$
$\frac{30 x - 12}{60} = \frac{20 x + 15}{60}$
$10 x = 27$
$x = \frac{27}{10} = 2 \frac{7}{10}$