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Question

If xsin245o×cos230o4cos260o=3sin245o×2cos230osin290o+2cos245o, then what is the value of x?

A
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B
1
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C
3
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D
4
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Solution

The correct option is C 3
Given,

xsin245×cos2304cos260=3sin245×2cos230sin290+2cos245

x(12)2×(32)24(12)2=3(12)2×2(32)2(1)2+2(12)2

3x81=942

3x8=98

3x=9

x=3

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