Question

If $\frac{x+y}{a-b}=\frac{2}{3}$, then $\frac{9x+9y}{10a-10b}=$

• A. $\frac{9}{10}$
• B. $\frac{20}{23}$
• C. $\frac{20}{27}$
• D. $\frac{3}{5}$

Answer 1

The correct option is D $\frac{3}{5}$

Given, $\frac{x+y}{a-b}$ $=$ $\frac{2}{3}$

To find $\frac{9x+9y}{10a-10b}$,

$=$ $\frac{9x+9y}{10a-10b}$

$=$ $\frac{9(x+y)}{10(a-b)}$

$=$ $\frac{9\times (x+y)}{10\times (a-b)}$

$=$ $\frac{9}{10}$ $\times$ $\frac{x+y}{a-b}$

As $\frac{x+y}{a-b}$ $=$ $\frac{2}{3}$, we get

$=$ $\frac{9}{10}$ $\times$ $\frac{2}{3}$

$=$ $\frac{3}{5}$

Therefore, $\frac{9x+9y}{10a-10b}$ $=$ $\frac{3}{5}$.