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Question

If circle x2+y2−kx−12y+4=0 touches x−axis , then k=`

A
12
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B
12
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C
4
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D
16
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Solution

The correct option is A 4
x2+y2kx12y+4=0 touches the Xaxis
if the Yco-ordinate of the centre of the circle is equal to the radius [centre of the circle is (k2,6)]
i.e. 6=k24+364
36=k24+364
k2=4×4
k=4

Hence, this is the answer.

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