Question

If circles are drawn on the sides of the triangle formed by the lines $x=0,y=0$ and $x+y=2$, as diameters, then the radical centre of three circles is

• A. $(0,0)$
• B. $(1,1)$
• C. $(2,1)$
• D. None of these

Answer 1

The correct option is D None of these

All three circles have their diameter on line $x+y=2$ i.e. their center lies on this line and hence centers are collinear.

There is no radical center for such $3$ circles.