Question

If ${Cl}_2$ is passed through hot aqueous $NaOH$, the products formed have $Cl$ in different oxidation states. These are indicated as :

• A. -1 and +1
• B. -1 and +5
• C. +1 and +5
• D. -1 and +3

Answer 1

The correct option is B -1 and +5

If ${Cl}_2$ is passed through hot aqueous $NaOH$, it results in the formation of sodium chloride and sodium chlorate as:

$6NaOH\left(Hotandconcentrated\right)+3{Cl}_2⟶5NaCl+NaCl{O}_3+3H_{2}O$

In $NaCl$, let oxidation state of $Cl$ be $x$.

$1+x=0$ or $x=-1$

In $NaCl{O}_3$, let oxidation state of $Cl$ be $y$.

$1+y+(-2)3=0$
$y-5=0$

$\therefore y=+5$

Thus, the obtained compounds have $Cl$ in $-1$ and $+5$ oxidation states.

Hence, option $B$ is correct.