If class mark is $25$ and class width is $10$ , then find the class.

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Solution

Let Lower Limit be $L$
$∴$ Upper Limit $= L + 10$ [ Since, Class Width $= 10$ ]

Now, we know that

$C l a s s M a r k = (L o w e r L i m i t + U p p e r L i m i t) \div 2$
$∴$ $(L + L + 10) \div 2 = 25$ [Class Mark $25$ given]
$\Rightarrow$ $2 L + 10 = 50$
$\Rightarrow$ $2 L = 40$

$\Rightarrow$ $L = 20$
$∴$ Lower Limit of the class $= 20$

Upper Limit of the class $= 20 + 10 = 30$

The required class is $20 - 30$

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If class mark is 25 and class width is 10, then find the class.

Let Lower Limit be L∴ Upper Limit =L+10 [ Since, Class Width =10]Now, we know that ClassMark=(LowerLimit+UpperLimit)÷2∴ (L+L+10)÷2=25 [Class Mark 25 given]⇒ 2L+10=50⇒ 2L=40⇒ L=20∴ Lower Limit of the class =20Upper Limit of the class =20+10=30The required class is 20−30

If class mark is $25$ and class width is $10$ , then find the class.