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Question

If co-ordinates of a point P is (1, 2, 2) then unit vector along the position vector of the point P will be

A
13(^i+2^j+2^k)
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B
^i+2^j+2^k
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C
13(^i2^j2^k)
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D
13(^i+^j+^k)
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Solution

The correct option is A 13(^i+2^j+2^k)
The position vector of point P will be the vector joining origin to P:
OP=(10)^i+(20)^i+(20)^K ( cordinates of P - (1,2,2))
OP=^i+2^j+2^K
Unit Vector of any given vector is given by : ^n=OPOP
^n=^i+2^j+2^k1+4+4=19(^i+2^j+2^k)=^i3+2^j3+2^k3

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