Question

If coefficient of range is $0.092$ and the largest value is $71$, the range is?

• A. $12$
• B. $13$
• C. $14$
• D. $16$

Answer 1

The correct option is A $12$

Coefficient of range$=\frac{x_m-x_0}{x_m+x_0}$

$0.092=\frac{71-x_0}{71+x_0}$

$0.092(71+x_0)=71-x_0$

$0.092x_0+x_0=71-71\times 0.092$

$x_0=\frac{71(1-0.092)}{1.092}=59.03\approx 59$

The smallest value of data is $59$

But the range$=x_m-x_0=71-59=12$