If collector current is 120mA and base current is 2mA and resistance gain is 3, what is power gain?
A
180
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B
10800
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C
1.8
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D
18
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Solution
The correct option is B10800 Ic=120mA, Ib=2mA⇒Ie=Ib+Ic (emitter current) ⇒Ie=120+2=122mA Resistance gain =3 d.c power gain =(currentgain)2×resistancegain =(IcIb)2×resistancegain =(1202)2×3=(60)2×3=3600×3=10800