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Question
If coordinates of P,Q, and R are (3,6),(-1,3) and (2,-1) respectively. Then area of △PQR is ____ square units.
If coordinates of P,Q, and R are (3,6),(-1,3) and (2,-1) respectively. Then area of △PQR is ____ square units.
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Solution
The correct option is B 12.5
Area of triangle having vertices (x1,y1),(x2,y2) and (x3,y3) is given by
=12×[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)]
Area of ΔPQR is given by
=12[3(3+1)−1(−1−6)+2(6−3)]
=12(12+7+6)=12.5 square units.
Area of triangle having vertices (x1,y1),(x2,y2) and (x3,y3) is given by
=12×[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)]
Area of ΔPQR is given by=12×[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)]
=12[3(3+1)−1(−1−6)+2(6−3)]
=12(12+7+6)=12.5 square units.
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