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Question

If coordinates of the centre and one end of a diameter of a circle are (7,3) and (5,7) respectively, then the coordinates of the other end of the diameter are

A
(6,2)
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B
(9,13)
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C
(12,4)
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D
(2,6)
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Solution

The correct option is B (9,13)
Let A(5,7), C(7,3)
Let B(x,y) be the other end of the diameter.
We know that in a circle, the centre bisects the diameter, so C is midpoint of AB.
(7,3)=(5+x2,7+y2)x=9, y=13B(9,13)

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