If copper is kept open in air, it slowly loses its shining brown surface and gains a green coating. It is due to the formation of:

C u C O_{3}

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C u S O_{4}

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C u C O_{3} . C u (O H)_{2}

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C u O

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Solution

The correct option is A $C u C O_{3} . C u (O H)_{2}$
Copper reacts with $C O_{2}$ present in the air and forms a green coating on its surface due to the formation of basic copper carbonate.

$2 C u + O_{2} + C O_{2} + H_{2} O \to C u C O_{3} . C u (O H)_{2}$

So, the correct option is $C$

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Question 16
If copper is kept in open air, it slowly loses its shining brown surface and gains a green coating. It is due to the formation of
(a) ${CuSO}_{4}$
(b) ${CuCO}_{3}$
(c) ${Cu(NO}_{3})_{2}$
(d) $CuO$

If copper is kept open in air, it slowly loses its shining brown surface and gains a green coating. It is due to ___ of copper.

Q. "In moist air, copper corrodes to produce a green layer on the surface". For this, the reaction is :

C u + H_{2} O + {C O}_{2} + O_{2} \to C u {C O}_{3} \cdot C u {(O H)}_{2}

If the statement is true enter 1 else enter 0.

C u C O_{3} \cdot C u (O H)_{2}

is also known as Malachite (green). State True or False.

Q. Copper loses its lustre due to the formation of greenish layer of copper ________ on its surface.

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If copper is kept open in air, it slowly loses its shining brown surface and gains a green coating. It is due to the formation of:

The correct option is A CuCO3.Cu(OH)2Copper reacts with CO2 present in the air and forms a green coating on its surface due to the formation of basic copper carbonate.2Cu+O2+CO2+H2O→CuCO3.Cu(OH)2So, the correct option is C

The correct option is A $C u C O_{3} . C u (O H)_{2}$
Copper reacts with $C O_{2}$ present in the air and forms a green coating on its surface due to the formation of basic copper carbonate.

$2 C u + O_{2} + C O_{2} + H_{2} O \to C u C O_{3} . C u (O H)_{2}$

So, the correct option is $C$