MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Standard Values of Trigonometric Ratios

If cos 1o c...

Question

If $cos 1^{o} cos 2^{o} cos 3^{o} . . . cos 179^{o} = x + 1$ , then $x$ is equal to

A

- 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

none of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $- 1$
$cos 1^{0} . cos 2^{0} . . . cos 90^{0} . . . cos (179^{0})$
$= 0$ since $cos 90^{0} = 0$
Hence
$x + 1 = 0$
$x = - 1$

Suggest Corrections

thumbs-up

0

Similar questions

Q. If f (x) = (x + 1)^{cot x} be continuous at x = 0, then f (0) is equal to
(a) 0
(b) 1/e
(c) e
(d) none of these

f (x) = \{\begin{array}{l} x \sin \frac{1}{x}, & x \neq 0 \\ 0, & x = 0 \end{array},

\lim_{x \to 0} f (x)

equals

(a) 1
(b) 0
(c) −1
(d) none of these

f (x) = |x - 3| and g (x) = f o f (x)

, then for x > 10, g ' (x) is equal to
(a) 1
(b) −1
(c) 0
(d) none of these

y = \tan^{- 1} (\frac{\sin x + \cos x}{\cos x - \sin x}), then \frac{d y}{d x}

is equal to
(a)

\frac{1}{2}

(b) 0
(c) 1
(d) none of these

l o g_{k} x . l o g_{5} k = l o g_{x} 5, k \neq 1, k > 0

, then x is equal to

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Trigonometric Ratios of Specific Angles

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Standard Values of Trigonometric Ratios

Standard X Mathematics

Join BYJU'S Learning Program

CrossIcon