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Standard Values of Trigonometric Ratios

If cos 1o c...

Question

If $cos 1^{o} cos 2^{o} cos 3^{o} . . . cos 179^{o} = x + 1$ , then $x$ is equal to

A

- 1

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B

0

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C

1

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D

none of these

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Solution

The correct option is A $- 1$
$cos 1^{0} . cos 2^{0} . . . cos 90^{0} . . . cos (179^{0})$
$= 0$ since $cos 90^{0} = 0$
Hence
$x + 1 = 0$
$x = - 1$

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