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Question

If cos1xcos1y2=α where 11x1,2y2,xy2 then for all 4x24xycosα+y2 is equal to

A
4sin2α2x2y2
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B
4cos2α+2x2y2
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C
4sin2α
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D
2sin2α
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Solution

The correct option is C 4sin2α
cos(cos1xcos1y2)=cosα
cosαx×y2+1x21y24(cosαxy2)2=(1x2)(1y24)
x2+y24xycosα=1cos2α=sin2α

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