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Question
If cos 3θ = cos θ − 6o,where 3 θ and θ − 6o are acute angles, find the value of θ
If cos 3θ = cos θ − 6o,where 3 θ and θ − 6o are acute angles, find the value of θ
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Solution
Given sin 3θ = cos(θ−6)
=> cos (90−3 θ) = cos(θ−6)
=> (90−3 θ) =(θ−6)
=> 4 θ =96
=> θ =24o
Given sin 3θ = cos(θ−6)
=> cos (90−3 θ) = cos(θ−6)
=> (90−3 θ) =(θ−6)
=> 4 θ =96
=> θ =24o
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