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Standard Values of Trigonometric Ratios

If cos 3 θ=√3...

Question

If $c o s 3 θ = \frac{\sqrt{3}}{2}$ ; $0 < 3 θ < 180^{\circ}$ , then value of $θ$ is:

A

15 degrees

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B

10 degrees

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C

0 degrees

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D

12 degrees

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Solution

The correct option is B
10 degrees

$c o s 3 θ = \frac{\sqrt{3}}{2} = c o s 30^{\circ}$

$3 θ = 30^{\circ}$

$θ = 10^{\circ}$

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Similar questions

cos θ + sec θ = \sqrt{3}

then the value of

{cos}^{3} θ + {sec}^{3} θ =

- \frac{π}{2} \leq θ \leq \frac{π}{2}

, then the minimum value of

{cos}^{3} θ + {sec}^{3} θ

cos 3 θ = \frac{\sqrt{3}}{2}

0 ° < 3 θ < 90 °

θ

(in degrees) is

x = sec θ - cos θ

y = {sec}^{3} θ - {sec}^{3} θ - {cos}^{3} θ,

then the value of

{(\frac{d y}{d x})}^{2}

x = 0,

- \frac{π}{2} < θ < \frac{π}{2}

,then the minimum value of

{cos}^{3} θ + {sec}^{3} θ

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