If cos3- -3-2- 0- - 3- - 90- the value of - in degrees is

Given: cos3 θ=√(3)/2 We know that cos 30^∘=√(3)/2 Comparing the two we get, 3θ nbsp;= 30^∘.... (given nbsp;0^∘ lt; 3θ lt; 90^∘) ⇒ nbsp;θ nbsp;= 10 ...

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If cos3θ= √3/...

Question

If $cos 3 θ = \frac{\sqrt{3}}{2}$ , $0 ° < 3 θ < 90 °$ , the value of $θ$ (in degrees) is
10

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Solution

The correct option is A 10
Given: $cos 3 θ = \frac{\sqrt{3}}{2}$
We know that $cos 30^{\circ} = \frac{\sqrt{3}}{2}$
Comparing the two we get,
$3 θ = 30^{\circ}$ .... (given 0 $^{\circ}$ < $3 θ$ < 90 $^{\circ}$ )
$\Rightarrow θ = 10^{\circ}$

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If cos3θ=√32, 0°<3θ<90°, the value of θ (in degrees) is10

The correct option is A 10Given: cos3θ=√32 We know that cos30∘=√32 Comparing the two we get, 3θ=30∘.... (given 0∘ < 3θ < 90∘) ⇒θ=10∘

If $cos 3 θ = \frac{\sqrt{3}}{2}$ , $0 ° < 3 θ < 90 °$ , the value of $θ$ (in degrees) is
10

The correct option is A 10
Given: $cos 3 θ = \frac{\sqrt{3}}{2}$
We know that $cos 30^{\circ} = \frac{\sqrt{3}}{2}$
Comparing the two we get,
$3 θ = 30^{\circ}$ .... (given 0 $^{\circ}$ < $3 θ$ < 90 $^{\circ}$ )
$\Rightarrow θ = 10^{\circ}$