If cos 4-sin 5-2 then -

The correct option is B (2n+1)π10 cos4θ +sin5θ =2 #160; #160;(Max Value) ⇒cos4θ =1 ; #160; #160; sin5θ =1 ⇒ 4θ =2nπ , 5θ= ...

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Standard XII

Mathematics

Range of Trigonometric Expressions

If cos 4θ+s...

Question

If $cos 4 θ + sin 5 θ = 2$ then $θ =$

\frac{n π}{2}

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\frac{(2 n + 1) π}{10}

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π

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\frac{2 π}{6}

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Solution

The correct option is B $\frac{(2 n + 1) π}{10}$
$cos 4 θ + sin 5 θ = 2$ (Max Value)
$\Rightarrow cos 4 θ = 1$ ; $sin 5 θ = 1$
$\Rightarrow 4 θ = 2 n π$ , $5 θ = n π + \frac{π}{2}$
or $θ = \frac{n π}{2}$ , $\frac{n π}{5} + \frac{π}{10} = \frac{(2 n + 1) π}{10}$

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If cos4θ+sin5θ=2 then θ=

The correct option is B (2n+1)π10cos4θ+sin5θ=2 (Max Value)⇒cos4θ=1 ; sin5θ=1⇒4θ=2nπ,5θ=nπ+π2or θ=nπ2,nπ5+π10=(2n+1)π10

If $cos 4 θ + sin 5 θ = 2$ then $θ =$

The correct option is B $\frac{(2 n + 1) π}{10}$
$cos 4 θ + sin 5 θ = 2$ (Max Value)
$\Rightarrow cos 4 θ = 1$ ; $sin 5 θ = 1$
$\Rightarrow 4 θ = 2 n π$ , $5 θ = n π + \frac{π}{2}$
or $θ = \frac{n π}{2}$ , $\frac{n π}{5} + \frac{π}{10} = \frac{(2 n + 1) π}{10}$