If cos4A – sin4A = 35, then 2cos2A–1=?
4/5
3/4
4/3
0
3/5
We know sin2A + cos2A = 1 and a2 - b2 = (a+b) (a-b)
Using the two identities, we have cos4A - sin4A = (cos2A - sin2A) (sin2A + cos2A) = (2 cos2A - 1) × 1 = 35
If cos4A – sin4A = 35, then 2cos2A−1= ?
If cos A - 3 sinA = -1 and A is an acute angle; then the value of sin A is?
If 42x=132,then x is