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Question

If cos4A – sin4A = 35, then 2cos2A–1=?


A

4/5

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B

3/4

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C

4/3

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D

0

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E

3/5

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Solution

The correct option is E

3/5


We know sin2A + cos2A = 1 and a2 - b2 = (a+b) (a-b)

Using the two identities, we have cos4A - sin4A = (cos2A - sin2A) (sin2A + cos2A) = (2 cos2A - 1) × 1 = 35


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