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Question

If cosA+cosB=12 and sinA+sinB=14
Prove that tan(A+B)2=12

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Solution

cosA+cosB=12sinA+sinB=14
2cos(A+B2)cos(AB2)=1212sin(A+B2)cos(AB2)=142
2/1
tan(A+B2)=14×2=12
tan(A+B2)=12

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