If cos A-34- then the value of sinA2sin5A2 is

The correct option is C 1132 (1/2)[2sin(A/2) sin(5A/2)] =(1/2)[cos((5A/2) (A/2) ) cos((5A/2)+(A/2))] =(1/2)[cos2A cos3A ] =(1/2)[(2cos^2 ...

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General Solution of sin theta = sin alpha

If cos A=34...

Question

If $cos A = \frac{3}{4}$ , then the value of $sin \frac{A}{2} sin \frac{5 A}{2}$ is

\frac{1}{32}

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\frac{11}{8}

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\frac{11}{32}

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\frac{11}{16}

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\sqrt{2 \frac{1}{4}} \times {(1 \frac{1}{3})}^{2} + 1 \div 3 \sqrt{3 \frac{3}{8}} =

{tan}^{- 1} (\frac{1}{1 + 1 + 1^{2}}) + {tan}^{- 1} (\frac{1}{1 + 2 + 2^{2}}) + {tan}^{- 1} (\frac{1}{1 + 3 + 3^{2}}) + . . . . . . . \infty

The sum of the series $t a n^{- 1} \frac{1}{2} + t a n^{- 1} \frac{1}{8} + t a n^{- 1} \frac{1}{18} + t a n^{- 1} \frac{1}{32} + \dots + \infty$ is

1 = \frac{1}{2} \{1 \times (1 + 1)\} 1 + 2 = \frac{1}{2} \{2 \times (2 + 1)\} 1 + 2 + 3 = \frac{1}{2} \{3 \times (3 + 1)\} 1 + 2 + 3 + 4 = \frac{1}{2} \{4 \times (4 + 1)\}

cos A = \frac{3}{4}

2 sin \frac{A}{2} sin \frac{5 A}{2} =

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