If cos A-4-5 and cos B-12-13- 3 -2-A- B-2 - find the value of the followingi cos A-bii sin A-B

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Sign of Trigonometric Ratios in Different Quadrants

If cos A=4/5 ...

Question

If $c o s A = \frac{4}{5}$ and $c o s B = \frac{12}{13}, \frac{3 π}{2} < A, B < 2 π$ , find the value of the following

$(i) c o s (A + b)$

$(i i) s i n (A - B)$

Open in App

Solution

Suggest Corrections

Similar questions

sin A = \frac{4}{5}, \frac{π}{2} < A < π

cos B = \frac{5}{13}, \frac{3 π}{2} < B < 2 π

sin (A + B)

cos (A - B)

tan (A - B)

If sin A = $\frac{4}{5}$ and cos B = - $\frac{12}{13}$ , where A and B lie in first

and third quadrant respectively, then cos(A + B) =

\tan 4 π - \cos \frac{3 π}{2} - \sin \frac{5 π}{6} \cos \frac{2 π}{3} = \frac{1}{4}

\sin \frac{13 π}{3} \sin \frac{8 π}{3} + \cos \frac{2 π}{3} \sin \frac{5 π}{6} = \frac{1}{2}

\sin \frac{13 π}{3} \sin \frac{2 π}{3} + \cos \frac{4 π}{3} \sin \frac{13 π}{6} = \frac{1}{2}

\sin \frac{10 π}{3} \cos \frac{13 π}{6} + \cos \frac{8 π}{3} \sin \frac{5 π}{6} = - 1

\tan \frac{5 π}{4} \cot \frac{9 π}{4} + \tan \frac{17 π}{4} \cot \frac{15 π}{4} = 0

cos A = \frac{4}{5}, cos B = \frac{12}{13}, \frac{3 π}{2} < A, B < 2 π

cos (A + B)

sin (A - B)

2 cos π 13 cos 9 π 13 + cos 3 π 13 + cos 5 π 13 = 0

Join BYJU'S Learning Program