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Question

If cosA=mcosB and cotA+B2=λtanBA2, then λ is

A
mm1
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B
m+1m
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C
m+1m1
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D
None of these
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Solution

The correct option is D m+1m1
Given, cosA=mcosBcosAcosB=m1

cosA+cosBcosAcosB=m+1m1

2cos(A+B2)cos(BA2)2sin(A+B2)sin(BA2)=m+1m1

cot(A+B2)=(m+1m1)tan(BA2)

But cot(A+B2)=λtan(BA2)λ=m+1m1

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