If cos -4-5- sin -5-13 and - - lie between 0 and -4- find tan2-

(Image) tan 2α #160; =tan( α +β +α β #160; ) #160; =tan( α +β #160; ) #160; +tan( α β #160; ) #160; #160; 1 tan( α +β #160; ) #16 ...

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Inequality

If cos α+β=...

Question

If $cos (α + β) = 4 / 5, sin (α - β) = 5 / 13$ and $α, β$ lie between $0$ and $\frac{π}{4}$ , find $tan 2 α$

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Solution

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Similar questions

cos (α + β) = \frac{4}{5}, sin (α - β) = \frac{5}{13}

α, β

\frac{π}{4}

tan 2 α =

cos (α + β) = \frac{4}{5}

sin (α - β) = \frac{5}{13}

α, β

0^{\circ}

45^{\circ}

tan 2 α

cos (α + β) = \frac{3}{5}, sin (α - β) = \frac{5}{13}

0 < α, β < \frac{π}{4},

tan (2 α)

0 < α, β < \frac{π}{4}, cos (α + β) = \frac{4}{5}, sin (α - β) = \frac{5}{13}

tan 2 α =

\sqrt{3} c o s e c 20^{\circ} s e c 20^{\circ} = 4

c o s (α + β) = \frac{4}{5}, s i n (α - β) = \frac{5}{13}

α, β

\frac{π}{4}

t a n 2 α

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