If cos-35-sin-513 and 0-4- then tan2- is equal to-

Cos(α+β)=35⇒tan(α+β)=43 sin(α β)=513⇒tan(α β)=512 Now, ⇒tan(2α)=tan((α+β)+(α β)) = tan(α+β)+tan(α β)1 tan(α+β)·tan(α β) =43+5121 43×512 =6316 ...

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Trigonometric Ratios for Sum of Two Angles

If cosα+β=35,...

Question

If $cos (α + β) = \frac{3}{5}, sin (α - β) = \frac{5}{13}$ and $0 < α, β < \frac{π}{4},$ then $tan (2 α)$ is equal to:

\frac{21}{16}

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\frac{63}{16}

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\frac{63}{52}

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\frac{33}{52}

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Solution

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Similar questions

cos (α + β) = \frac{3}{5}, sin (α - β) = \frac{5}{13}

0 < α, β < \frac{π}{4},

tan (2 α)

0 < α, β < \frac{π}{4}, cos (α + β) = \frac{4}{5}, sin (α - β) = \frac{5}{13}

tan 2 α =

cos (α + β) = \frac{4}{5}

sin (α - β) = \frac{5}{13}

0 \leq α, β \leq \frac{π}{4}

tan 2 α

cos (α + β) = \frac{4}{5}, sin (α - β) = \frac{5}{13}

α, β

\frac{π}{4}

tan 2 α =

cos (α + β) = 4 / 5, sin (α - β) = 5 / 13

α, β

0

\frac{π}{4}

tan 2 α

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