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Trigonometric Ratios of Common Angles

If cos α+β+...

Question

If $c o s (α + β) + s i n (α - β) = 0$ and $2010 t a n β + 1 = 0$ then $t a n α$ is equal to

A

1

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B

- 1

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C

2010

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D

\frac{1}{2010}

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Solution

The correct option is B $- 1$

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Similar questions

cos (α + β) = \frac{3}{5}, sin (α - β) = \frac{5}{13}

0 < α, β < \frac{π}{4},

tan (2 α)

sin (α + β) = 1, sin (α - β) = \frac{1}{2}

tan (α + 2 β) tan (2 α + β)

α, β ϵ (0, π / 2)

sin (α + β) = 1

sin (α - β) = \frac{1}{2}

0 \leq α, β \leq \frac{π}{2}

then find the value of

tan (α + 2 β)

tan (2 α + β)

s i n (α + β) = 1

s i n (α - β) = \frac{1}{2},

0 \leq α, β \leq \frac{π}{2},

then find the values of

t a n (α + 2 β)

t a n (2 α + β)

sin (α + β) = 1

sin (α - β) = \frac{1}{2}

tan (α + 2 β) tan (2 α + β) =

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