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Question

If cosα+cosβ=a,sinα+sinβ=b, then cos(αβ) is equal to

A
2aba2+b2
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B
a2b2a2b2
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C
a2+b222
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D
b2a2a2+b2
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Solution

The correct option is D a2+b222
given cosα+cosβ=a,sinα+sinβ=b

a2=cos2α+cos2β+2cosαcosβ

b2=sin2α+sin2β+2sinαsinβ

a2+b2=cos2α+sin2α+cos2β+sin2β+2cosαcosβ+2sinαsinβ

=2+2(cosαcosβ+sinαsinβ)

=2+2cos(αβ)

a2+b2=2+2cos(αβ)

cos(αβ)=a2+b222

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