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B
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C
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D
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Solution
The correct option is C cosα+cosβ+cosγ=0andsinαisinβ+sinγ=0Leta=cosαisinα;b=cosβiisinβandc=cosγ+isinγ.Thereforea+b+c=(cosα+cosβ+cosγ)+i(sinα+sinβ+sinγ)=0+i0=0ifa+b+c=0,thena3+b3+c3=3abcor(cosα+isinα)3+(cosβ+isinβ)3+(cosγ+isinγ)3=3(cosα+isinα)(cosβ+isinβ)(cosγ+isinγ)⇒(cos3γ+isin3γ)+(cos3β+isin3β)+(cos3γ+isin3γ)=3[cos(α+β+γ)+isin(α+β+γ)]orcos3α+cos3β+cos3)γ=3cos(α+β+γ).