Ifcosɑcoshβ=1, then β=?
logsec(ɑ/2)
logtanɑ
log(secɑ+tanɑ)
logsin(ɑ/2)
Find the value β:
cosɑcoshβ=1coshβ=secɑβ=cosh-1(secɑ)=log(secɑ+sec2ɑ-1)=log(secɑ+tanɑ)
Hence, the correct answer is option (C).
If α and β are different complex numbers with = 1, then find.