If cos-1-2- x-1-x - and cos-1-2- y-1-y - xy - 0 x- y- - - - R then

The correct options are A sin(α+β+γ)=sinγ ∀γ ∈ R B cosαcosβ=1 ∀ α, β ∈ R C (cosα+cosβ)^2=4 ∀ α, β ∈ R D sin(α+β+γ)=sinα+sinβ+sinγ ∀ α, β, ...

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If cosα=1/2...

Question

If $cos α = \frac{1}{2} (\begin{matrix} x + \frac{1}{x} \end{matrix})$ and $cos β = \frac{1}{2} (\begin{matrix} y + \frac{1}{y} \end{matrix}), (x y > 0) x, y, α, β \in R$ then

sin (α + β + γ) = s i n γ \forall γ \in R

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cos α cos β = 1 \forall α, β \in R

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(cos α + cos β)^{2} = 4 \forall α, β \in R

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sin (α + β + γ) = sin α + sin β + sin γ \forall α, β, γ \in R

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c o s α + c o s β + c o s γ = s i n α + s i n β + s i n γ = 0

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0 < α, β, γ < π / 2

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tan α < \frac{sin α + sin β + sin γ}{cos α + cos β + cos γ} < tan γ

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