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Question

If cosπ33cos2π33cos4π33cos8π33cos16π33cos=1m, then m =

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Solution

cosπ33.cos2π33.cos4π33.cos8π33.cos16π33=sin25π/3325sinπ/33
(standard Result)
=sin32π/3332sinπ/33=sin(π/33)32sinπ/33
=sinπ/3332sinπ/33
=132

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