If cos x-y- cos x- cos x-y are three distinct numbers which are harmonic progression and cos x-cos y then 1-cos y-A- cos 2 xB- -cos 2 xC- cos 2 x-1D- cos 2 x-2

The correct option is A cos^2x b=2ac/a+c ⇒ cos x=2 cos ( x y )cos ( x+y )/cos ( x y )+cos ( x+y ) ⇒ 1+cos y=cos^2x ...

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If cos x-y, c...

Question

If $c o s (x - y), c o s x, c o s (x + y)$ are three distinct numbers which are harmonic progression and $c o s x \neq c o s y$ then $1 + c o s y =$

$c o s^{2} x$

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$- c o s^{2} x$

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$c o s^{2} x - 1$

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$c o s^{2} x - 2$

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Similar questions

If $c o s (x - y), c o s x, c o s (x + y)$ are three distinct numbers which are harmonic progression and $c o s x \neq c o s y$ then $1 + c o s y =$

\frac{cos x}{cos y} = 2

cos (x - y) = \frac{\sqrt{3}}{2}

y =

cos x + cos y = a, cos 2 x + cos 2 y = b, cos 3 x + cos 3 y = c

cos x + cos y + c o s z

= 0 =

sin x + sin y + sin z

{cos}^{2} (\frac{x - y}{2}) =

0 < x, y < π

cos x + cos y - cos (x + y) = \frac{3}{2},

sin x + cos y

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