Given,
cosA=AdjacentSideHypotenuse=513
We know that,
sinA=oppositeSideHypotenuse
From Pythagoras theorem,
(Hypotenuse)2=(oppositeSide)2+(adjacentSide)2
132=52+(oppositeSide)2
(oppositeSide)2=169−25=144
(oppositeSide)=12
tanA=OppositeSideAdjacentSide=125
Therefore,
2sinθ−cos2θ2sinθcosθ×1tan2θ
=2(1213)−(513)22(1213)(513)×1(125)2
=(24×13169)−(25169)2(1213)(513)×25144
=(312−25169)(120169)×25144
=287120×25144
=28724×5144
=14353456