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Question

If cos(xy)=x, then dydx is equal to?

A
y+cosec(xy)x
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B
y+sin(xy)x
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C
y+cos(xy)x
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D
y+cosec(xy)x
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Solution

The correct option is D y+cosec(xy)x
cos(xy)=x
Differentiating with respect to x :-
sin(xy).[y+xdydx]=1
y+xdydx=1sin(xy)
xdydx=[1sinxy+y]
dydx=1x[1sinxy+y]=(y+cosecxy)x

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