If cos y - x cos a - y and dy - dx - k -1- x 2-2 x cos a then the value of k isA- sin aB- cos aC- 1 D- -sin a

The correct option is A sin ax=cos y/cos(a+y) ⇒dx/dy=sin a/cos^2(a+y) ⇒dy/dx=cos^2y/x^2 sin a =sin a/1+x^2 2x cos a ⇒ K sin a ...

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Quotient Rule of Differentiation

If cos y = x ...

Question

If cos y = x cos(a+y) and $\frac{d y}{d x} = \frac{k}{1 + x^{2} - 2 x c o s a}$ then the value of k is

sin a

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cos a

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- sin a

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cos y = x cos (a + y)

cos a \neq \pm 1

\frac{d y}{d x}

\frac{d y}{d x} = \frac{A}{1 + x^{2} - 2 x c o s a^{'}},

If $c o s y = x c o s (a + y), c o s a \neq 1$ prove that $\frac{d y}{d x} = \frac{c o s^{2} (a + y)}{s i n a}$

cos y = x cos (a + y)

cos a \neq \pm 1

\frac{d y}{d x} = \frac{{cos}^{2} (a + y)}{sin a}

$I f c o s y = x c o s (a + y), w i t h c o s a \neq 1, p r o v e t h a t \frac{d y}{d x} = \frac{c o s^{2} (a + y)}{s i n a} .$

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