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Question

If cos3θ=cos3α, then the value of sinθ can be given by

A
±sinα
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B
sin(π3±α)
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C
sin(2π3+α)
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D
sin(2π3α)
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Solution

The correct options are
B ±sinα
C sin(2π3+α)
D sin(2π3α)
Given, cos3θ=cos3α
Therefore general solution can be given as,
3θ=2nπ±3α, where nZ
θ=2nπ3±α
sinθ=sin(2nπ3±α)
Hence option A, C and D are correct choices corresponding to n=0 and n=1

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