Differentiation of Inverse Trigonometric Functions
If cos3θ=co...
Question
If cos3θ=cos3α, then the value of sinθ can be given by
A
±sinα
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B
sin(π3±α)
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C
sin(2π3+α)
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D
sin(2π3−α)
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Solution
The correct options are B±sinα Csin(2π3+α) Dsin(2π3−α) Given, cos3θ=cos3α Therefore general solution can be given as, ⇒3θ=2nπ±3α, where n∈Z ⇒θ=2nπ3±α ⇒sinθ=sin(2nπ3±α) Hence option A, C and D are correct choices corresponding to n=0 and n=1