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Question

If cosA=mcosB, then write the value of cotA+B2cotAB2

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Solution

We have.
cosA=mcosB,cosAcosB=mcosAcosB+1=m+1cosA+cosBcosB=m+1 (i)
Again,
cosAcosB=mcosAcosB1=m1cosAcosBcosB=m1(ii)
Dividing equation (i) by equation (ii), we get
cosA+cosBcosBcosAcosBcosB=m1m1cosA+cosBcsosAcosB=fracm1m12cos(A+B2)cos(AB2)2sin(A+B2)sin(AB2)=m+1m1cot(A+B2)cot(AB2)=m+1m1cot(A+B2)cot(AB2)=1+m1mcot(A+B2)cot(AB2)=1+m1m


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